XML to JSON Sergey Svistunov

Convert 1,000,000 person records from XML to JSON as fast as possible.

Input

XML document on STDIN:

<?xml version="1.0" encoding="UTF-8"?>
<persons>
    <person id="1512376">
        <age>30</age>
        <height>169.1</height>
        <married>true</married>
        <phone code="+6"><number>1283603279</number></phone>
        <phone code="+6"><number>1659964668</number></phone>
    </person>
    ...
</persons>

Output

One JSON object per person to STDOUT, preserving order:

{
    "id": 1512376,
    "age": 30,
    "height": 169.1,
    "married": true,
    "phones": [
        {
            "code": "+6",
            "number": 1283603279
        },
        {
            "code": "+6",
            "number": 1659964668
        }
    ]
}

Constraints

  • Preserve the order of persons
  • Omit the phones field if the phone array is empty
  • Maximum number of phones per person is 3
Back to listOct 8, 2026 04:00Karthik ReddyKarthik ReddyError
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Run Statistics
#DateScoreWall TimeCPU UserCPU SystemMemoryError
1Oct 8, 2026 04:010457,678,671341,305,000105,324,00094,392,320diff: map[string]any{ ... // 3 identical entries "married": bool(false), "phones": []any{map[string]any{"code": string("+9"), "number": s"1134425149"}}, + "s0": string("n136534717 o92685265 p1000000 ws1999009 amp0 ap0 o0 b0"), + "s1"...
2Oct 8, 2026 04:010459,570,165342,164,000106,315,00094,392,320diff: map[string]any{ ... // 2 identical entries "married": bool(true), "phones": []any{map[string]any{"code": string("+3"), "number": s"1320850859"}, map[string]any{"code": string("+0"), "number": s"1314456516"}}, + "s0": string("n13...
3Oct 8, 2026 04:010457,688,471341,393,000105,281,00094,392,320diff: map[string]any{ ... // 3 identical entries "married": bool(true), "phones": []any{map[string]any{"code": string("+2"), "number": s"1930554199"}, map[string]any{"code": string("+5"), "number": s"1474652100"}}, + "s0": string("n13...